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Converting MOI from SI to imperial ??? How?

JEL

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Hello :)

I am trying to calculate a set of 'moments-of-inertia' values from SI-standard to imperial standard, but I'm not sure I'm doing it correctly. So I was hoping someone could perhaps double-check my numbers.

I have these original values:

Ixx = 1.1829 * 10^8 kg/m2
Iyy = 8.8239 * 10^8 kg/m2
Izz = 9.0297 * 10^8 kg/m2

and my calculated results are this (decimals omitted on purpose):

Ixx = 24227689
Iyy = 180727629
Izz = 184942743

Theyre supposed to be in lbs/ft2 (which I believe is aka: Slug-ft^2, which is what I'm trying to convert into), but like I said I'm not sure I'm doing the conversion correctly.

I'm dividing the SI-numbers with 4.88243 to get the lbs/ft2

Can someone confirm my results, or explain how to do a correct conversion (ultimately into Slug-ft^2)

Thanks :)
JEL
 
The units for inertia are mass * length^2. So your original values should have units of kg * m^2, and not kg / m^2. If you calculate the conversion from kg * m^2 to lb * ft^2, you should get the correct result.

Regards
 
A trick for using English units: always differentiate between pounds force and pounds mass (lbf and lbm). I wouldn't use pounds anything anyway. The most useful units are slug ft^2
 
A trick for using English units: always differentiate between pounds force and pounds mass (lbf and lbm). I wouldn't use pounds anything anyway. The most useful units are slug ft^2

And pounds sterling! And English pounds, and Egyptian pounds, especially if you're in a taxi in Egypt... read about a scam in a Lonely Planet. And went there.
 
A trick for using English units: always differentiate between pounds force and pounds mass (lbf and lbm). I wouldn't use pounds anything anyway. The most useful units are slug ft^2

There's useful imperial units?
 
Now you see why metric was invented.

EDIT: No base 12 or anything, all base 10...

"4 plus 4 is 10... IN BASE 8! I'm FINE."

Ah, poor, poor confused GLaDOS.
 
The units for inertia are mass * length^2. So your original values should have units of kg * m^2, and not kg / m^2. If you calculate the conversion from kg * m^2 to lb * ft^2, you should get the correct result.

Regards

Well, I just copy-pasted the values directly from the pdf-document :)
(you can see a snapshot here: http://home.tiscali.dk/8x066050/JELAIR/FlightTestCenter/TEMP/ )



Thank you very much :) Now I get values I can understand :)
JEL
 
There's useful imperial units?

Yes, a very good unit the Horse Power, you can see exactly what it does. Also its not a vector, it only travels in a straight line.

N.
 
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